Suggested: y=x^3 log x - if u=log(x3+y3+z3-3xyz) show that d2u/dx2+d2u/dy2+d2u/dz2=-3/(x+y+z)2 - if log(x+y/3)=1/2(logx+logy) then find the value of x/y+y/x - if u=log(x3+y3+z3-3xyz) show that dy/dx+du/dy+du/dz=3/x+y+z - log(x+y/3)=1/2(log x+log y) then x/y+y/x - x^3d^3y/dx^3+3x^2 d^2y/dx^2+xdy/dx+y=x+log x - y=x^3 log x Browse related:
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